#include <string.h>
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char *
stpcpy (char *dst, const char *src); |
char *
strcpy (char * restrict dst, const char * restrict src); |
char *
strncpy (char * restrict dst, const char * restrict src, size_t len); |
The strncpy function copies at most len characters from src into dst. If src is less than len characters long, the remainder of dst is filled with ‘\0’ characters. Otherwise, dst is not terminated.
#include <string.h> #include <stdio.h> int main() { char one[50] = {"abcdefgh"}; printf("String before strcpy %s\n",one); strcpy(one,"Hello"); printf("String after strcpy %s\n",one); strncpy(one + 5, " ",1); strncpy(one + 6, "World",5); printf("String after strncpy %s\n",one); return 0; }
Output
String before strcpy abcdefgh String after strcpy Hello String after strncpy Hello World
char chararray[6]; (void)strncpy(chararray, "abc", sizeof(chararray));
The following sets chararray to "abcdef:"
char chararray[6]; (void)strncpy(chararray, "abcdefgh", sizeof(chararray));
Note that it does not NULL terminate chararray because the length of the source string is greater than or equal to the length argument.
The following copies as many characters from input to buf as will fit and NULL terminates the result. Because strncpy does not guarantee to NULL terminate the string itself, this must be done explicitly.
char buf[1024]; (void)strncpy(buf, input, sizeof(buf) - 1); buf[sizeof(buf) - 1] = ’\0’;
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